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aggregator    
aggregator
n 1: a person who collects things [synonym: {collector},
{aggregator}]



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  • How to get row number for 0 by using Aggregator for null input row
    You'r right There is no input row coming through pipe line and aggregator doesn't get any rows to do the operation I assume aggregator should get some value default value for 0, or in next transformation Expression, I can set default value 0 for this total number However, it seems the result always is the row number from cache (Last run)
  • Aggregator without any group by
    now pass all the ports ID,SAL,O_Count to aggregator t r and connect to next t r or tgt If you dont check any groupby port in aggregator bydefault it passes last record to the next transformation so here last record(O_count) contains max record number and also it our required count Any Queryes or sujessions @ chs sekhar@gmail com Cheers
  • Aggregator does not work properly - network. informatica. com
    Aggregator does not work properly We have faced issue with aggregator transformation (using sum on a field having 2 decimal values), and it truncates So we end up with difference of 0 01, compare to database simple SQL aggregation query for SUM()
  • ) How to return First Last record via one Aggregator Transformation . . .
    Let's take an example case where you have three input ports to the AGG, namely FULL_NAME (String(60)), ZIP_CODE (String(5)), and ADDRESS (String( 40))
  • How to transfer all unique rows to 1 target and all . . . - Informatica
    Source-->SrcQualifier-->Aggregator(group by this column and find count also)--> then use joiner (use the column from Source qualifier and join the data from Aggregator as source qualifier col=aggregator col) --> Router (insert into t1 for count>1 and for count=1 insert into t2) t1 is for duplicate records and it will contain
  • Union Transformation - Union (Not Union All)
    You can also go for Aggregator Transformation by doing groupby on all the ports as Vani has already specify in the reply If your Source is Relational than you can go for select distinct option in Source Qualifier properties also Regards, DJ
  • i want to load employee details who are getting max and min sal from . . .
    Connect two aggregator transformations to the source qualifier Connect empno,sal,deptno to both the aggregators Group by deptno and get min and max sal in the respective aggregator Connect the output of both the aggregators to the union transformation
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