英文字典中文字典


英文字典中文字典51ZiDian.com



中文字典辞典   英文字典 a   b   c   d   e   f   g   h   i   j   k   l   m   n   o   p   q   r   s   t   u   v   w   x   y   z       







请输入英文单字，中文词皆可：

contained    音标拼音: [kənt'end]
包含的

包含的

contained
自主式; 自含式 SCNTN

contained
含

contained
adj 1: gotten under control; "the oil spill is contained"

Contain \Con*tain"\, v. t. [imp. & p. p. {Contained}; p. pr. &
vb. n. {Containing}.] [OE. contenen, conteinen, F. contenir,
fr. L. continere, -tentum; con- tenere to hold. See
{Tenable}, and cf. {Countenance}.]
1. To hold within fixed limits; to comprise; to include; to
inclose; to hold.
[1913 Webster]

Behold, heaven and the heaven of heavens can not
contain thee; how much less this house! --2 Chron.
vi. 18.
[1913 Webster]

When that this body did contain a spirit. --Shak.
[1913 Webster]

What thy stores contain bring forth. --Milton.
[1913 Webster]

2. To have capacity for; to be able to hold; to hold; to be
equivalent to; as, a bushel contains four pecks.
[1913 Webster]

3. To put constraint upon; to restrain; to confine; to keep
within bounds. [Obs., exept as used reflexively.]
[1913 Webster]

The king's person contains the unruly people from
evil occasions. --Spenser.
[1913 Webster]

Fear not, my lord: we can contain ourselves. --Shak.
[1913 Webster]


请选择你想看的字典辞典：
单词字典翻译
Contained查看　Contained　在百度字典中的解释百度英翻中〔查看〕
Contained查看　Contained　在Google字典中的解释Google英翻中〔查看〕
Contained查看　Contained　在Yahoo字典中的解释Yahoo英翻中〔查看〕

安装中文字典英文字典查询工具!


中文字典英文字典工具:
选择颜色:
输入中英文单字

































































英文字典中文字典相关资料:


  • How to Solve a Multi-Atwood Machine Assembly - Physics Forums
    AM stands for "Atwood machine" It is an ideal pulley supported by a string An ideal pulley is massless and changes the direction of the tension but not its magnitude Two masses are attached to the ends of a massless inextensible string that goes over the pulley
  • How Do You Calculate the Second Mass in an Atwood Machine Problem?
    In the Atwood machine problem, the first block has a mass of 3 66 kg, and the second block's mass is unknown, with the system accelerating downward at 0 255g The equation derived for the second mass, M, is M = m (g - a) (g + a), leading to a first solution of 6 17 kg The discussion reveals confusion over the hint suggesting two solutions, which is clarified by considering the possibility of
  • Lagrange EQ for a Double Atwood Machine - Physics Forums
    The discussion revolves around solving a double Atwood machine problem using Lagrangian mechanics The user initially struggles with setting up the correct Lagrangian and believes their formulation differs from the solution manual After some back and forth, it is determined that the discrepancy arises from the direction chosen for one of the generalized coordinates, which affects the sign of
  • Atwood Machine, deriving equation for acceleration - Physics Forums
    The discussion focuses on understanding the dynamics of an Atwood Machine, specifically deriving the equations for the acceleration of the masses involved The user is attempting to show that the acceleration of the movable pulleys is the average of the accelerations of the two lower masses and is seeking guidance on how to proceed with the calculations They have correctly identified
  • A Question about the Double Atwood Machine • Physics Forums
    The double Atwood machine shown in Fig 4-50 has frictionless, massless pulleys and cords Determine (a) the acceleration of masses m1, m2 and m3, and (b) the tensions FT1 and FT3 in the cords
  • Atwood Machine Help: Magnitude of T When M1 Goes to Infinity
    In an Atwood machine with two masses, as m1 approaches infinity while m2 remains constant, the tension (T) in the rope can be analyzed through the forces acting on m2 The key point is that m2 will accelerate upwards at a rate of g due to the overwhelming weight of m1, which effectively pulls m2 upward without significant resistance The tension in the rope is determined by the forces acting
  • Calculating % Error on Atwoods Machine Lab - Physics Forums
    hi all im doing a lab on the atwoods machine basically i ahve calulated gravity as eqaul to 7 09 m s^2 so i am way off because tis really 9 81 its because
  • What is the tension in an Atwood machine when one mass is infinitely . . .
    An Atwood machine consists of two blocks (of masses m_1 and m_2) tied together with a massless rope that passes over a fixed, perfect (massless and frictionless) pulley For all parts of this problem, take upward to be the positive direction and take the gravitational constant, g, to be
  • Solved 1) Simple Atwoods machine: a. (lab manual) Describe - Chegg
    1) Simple Atwood's machine: a (lab manual) Describe a simple Atwood's machine using the diagram b (Ex 5 21) Draw separate free-body diagrams for m and m2 Identify the action-reaction pair on the diagrams using Newton's Third Law m ; m2 c (lab manual, Ch 5 8, Ex 5 21) Consider the net forces including the tension on each object and combine the equations to verify Eq (1) in the lab
  • Atwood Machine: Find m1s Descent and Velocity - Physics Forums
    Homework Statement In the Atwood machine shown below, m1 = 2 00 kg and m2 = 7 50 kg The masses of the pulley and string are negligible by comparison The pulley turns without friction and the string does not stretch The lighter object is released with a sharp push that sets it into motion at





中文字典-英文字典  2005-2009