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  • Who first defined truth as adæquatio rei et intellectus?
    António Manuel Martins claims (@44:41 of his lecture quot;Fonseca on Signs quot;) that the origin of what is now called the correspondence theory of truth, Veritas est adæquatio rei et intellectus
  • factorial - Why does 0! = 1? - Mathematics Stack Exchange
    The theorem that $\binom {n} {k} = \frac {n!} {k! (n-k)!}$ already assumes $0!$ is defined to be $1$ Otherwise this would be restricted to $0 <k < n$ A reason that we do define $0!$ to be $1$ is so that we can cover those edge cases with the same formula, instead of having to treat them separately We treat binomial coefficients like $\binom {5} {6}$ separately already; the theorem assumes
  • Difference between PEMDAS and BODMAS. - Mathematics Stack Exchange
    Division is the inverse operation of multiplication, and subtraction is the inverse of addition Because of that, multiplication and division are actually one step done together from left to right; the same goes for addition and subtraction Therefore, PEMDAS and BODMAS are the same thing To see why the difference in the order of the letters in PEMDAS and BODMAS doesn't matter, consider the
  • Prove that $1^3 + 2^3 + . . . + n^3 = (1+ 2 + . . . + n)^2$
    HINT: You want that last expression to turn out to be $\big (1+2+\ldots+k+ (k+1)\big)^2$, so you want $ (k+1)^3$ to be equal to the difference $$\big (1+2+\ldots+k+ (k+1)\big)^2- (1+2+\ldots+k)^2\; $$ That’s a difference of two squares, so you can factor it as $$ (k+1)\Big (2 (1+2+\ldots+k)+ (k+1)\Big)\; \tag {1}$$ To show that $ (1)$ is just a fancy way of writing $ (k+1)^3$, you need to
  • Good book for self study of a First Course in Real Analysis
    Does anyone have a recommendation for a book to use for the self study of real analysis? Several years ago when I completed about half a semester of Real Analysis I, the instructor used "Introducti
  • Why is $\infty\times 0$ indeterminate? - Mathematics Stack Exchange
    "Infinity times zero" or "zero times infinity" is a "battle of two giants" Zero is so small that it makes everyone vanish, but infinite is so huge that it makes everyone infinite after multiplication In particular, infinity is the same thing as "1 over 0", so "zero times infinity" is the same thing as "zero over zero", which is an indeterminate form Your title says something else than
  • Show that $n^3-n$ is divisible by $6$ using induction
    This answer is with basic induction method when n=1, $\ 1^3-1 = 0 = 6 0$ is divided by 6 so when n=1,the answer is correct we assume that when n=p , the answer is correct so we take, $\ p^3-p $ is divided by 6 then, when n= (p+1), $$\ (p+1)^3- (p+1) = (P^3+3p^2+3p+1)- (p+1)$$ $$\ =p^3-p+3p^2+3p+1-1 $$ $$\ = (p^3-p)+3p^2+3p $$ $$\ = (p^3-p)+3p (p+1) $$ as we assumed $\ (p^3-p) $ is
  • Are we sinners because we sin or do we sin because we are sinners?
    Thank you for the answer, Geoffrey From what you wrote : 'Are we sinners because we sin?' can be read as 'By reason of the fact that we sin, we are sinners' I think I can understand that But when it's connected with Original Sin, am I correct if I make the bold sentence become like this "By reason of the fact that Adam Eve sin, human (including Adam and Eve) are sinners" ? Please CMIIW
  • Direct proof that integral of $1 x$ is $\ln (x)$ [closed]
    Continue to help good content that is interesting, well-researched, and useful, rise to the top! To gain full voting privileges,
  • When 0 is multiplied with infinity, what is the result?
    What I would say is that you can multiply any non-zero number by infinity and get either infinity or negative infinity as long as it isn't used in any mathematical proof Because multiplying by infinity is the equivalent of dividing by 0 When you allow things like that in proofs you end up with nonsense like 1 = 0 Multiplying 0 by infinity is the equivalent of 0 0 which is undefined





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