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  • Parents that are heterozygous for having freckles (dominant) are . . .
    When heterozygous parents (Ff) are crossed, 75% of their offspring will have freckles, either homozygous (FF) or heterozygous (Ff) The Punnett square reveals this distribution of genotypes Therefore, the correct statement is that seventy-five percent of the offspring have freckles
  • Parents that are heterozygous for having freckles (dominant) are . . .
    Parents that are heterozygous for having freckles (dominant) are crossed Which correctly describes their offspring? A 100% will have freckles B 75% will have freckles, and 25% will not C 50% will have freckles, and 50% will not D 25% will have freckles, and 75% will not
  • Parents that are heterozygous for having freckles (dominant) are . . .
    When two parents that are heterozygous for a trait are crossed, in this case freckles, we can predict the possible outcomes of their offspring using a Punnett square In this scenario, each parent has the genotype F f for freckles, where F represents the dominant allele for freckles and f represents the recessive allele for no freckles
  • Parents that are heterozygous for having freckles (dominant) are . . .
    When two heterozygous parents (Ff) for freckles are crossed, 75% of their offspring will exhibit freckles due to the dominant allele The ratio of genotypes includes 25% homozygous dominant (FF), 50% heterozygous (Ff), and 25% homozygous recessive (ff) Therefore, the answer to the question is that seventy-five percent have freckles
  • Parents that are heterozygous for having freckles (dominant) are . . .
    When two heterozygous parents (Ff) for freckles are crossed, 75% of the offspring will have freckles This is because the offspring can inherit combinations of alleles that result in either the dominant or recessive phenotype Hence, the correct answer is C: Seventy-five percent have freckles
  • [FREE] Parents that are heterozygous for having freckles (dominant) are . . .
    When two heterozygous parents for freckles are crossed, 75% of their offspring will have freckles This is determined using a Punnett square, which shows that 3 out of 4 offspring will display the trait due to the dominant allele Therefore, the correct answer is option C
  • Parents that are heterozygous for having freckles (dominant) are . . .
    When two heterozygous parents (Ff) are crossed, 75% of their offspring will have freckles, and the correct answer is option C This is explained using a Punnett square showing the ratios of the genotypes and phenotypes of the offspring The ratio of offspring with freckles is 75% due to the presence of dominant alleles (F)
  • Parents that are heterozygous for having freckles (dominant) are . . .
    Since freckles are a dominant trait, any individual with at least one dominant allele (F) will have freckles Hence, both the FF and F f individuals will express freckles To find the percentage of offspring with freckles, we add the percentages of FF and F f: 25% + 50% = 75% Thus, 75% of the offspring will have freckles
  • Parents that are heterozygous for having freckles (dominant) are . . .
    In this case, having freckles is a dominant trait represented by the allele 'F', while the allele for not having freckles is recessive and represented by 'f' When two heterozygous parents (Ff x Ff) are crossed, we can use a Punnett square to predict the genotypes of their offspring The possible combinations from this cross are:
  • Parents that are heterozygous for having freckles (dominant) are crossed.
    Having freckles (f) is dominant over not having freckles (f) a parent with freckles is crossed with a parent without freckles the punnett square shows the possible genotypes of the offspring what is the probability that an offspring will have a homozygous dominant genotype? 50% % what is the probability that an offspring will have a heterozygous genotype? 25% % what is the probability that





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