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  • algorithm - Time Limit Exceeded for Binary Search in Python . . .
    I have created a binary search program in python but I am getting "time limit exceeded" for one of the test cases Any idea how I can optimize my code to reduce the running time? My code basically finds the index of the median term and compares the query to the integer at the median
  • How to overcome Time Limit Exceed (TLE) - GeeksforGeeks
    In competitive programming, time complexity helps you predict whether your solution will run fast enough or cause a TLE (Time Limit Exceeded) Most problems have input size limits (like N ≤ 10⁵ or N ≤ 10⁶)
  • Beating the Clock: How to Avoid Time Limit Exceeded (TLE . . .
    You need lightning-fast solutions like O(log n) (Binary Search) or O(1) (Math formulas) 💡 Example: Searching in a massive sorted dataset ⚡ Pro Tip: Always read the constraints
  • How do improve code to pass Time Limit Exceeded test on . . .
    Like if n1 is 2 and target is 9, you can do a binary search for (9 - 2) If it’s not there, move on and try using the next number in the list as n1 Binary searching is O(log(n)), whereas iterating is O(n), so it’ll be much faster
  • c - Time limit exceeded in binary search - Stack Overflow
    By setting loc to -1 you could even improve your code, by getting rid of the flag: int BinarySearch(int low,int high,int *a,int item) { int mid= (low + high) 2, loc=-1; while (item!= a[mid] low <= high) { if(a[mid]==item){ loc=mid; } else if (item < a[mid]) high = mid - 1; else low = mid + 1; } return loc; }
  • Ways to remove TLE - GeeksforGeeks
    While solving problems on any online judge sometimes it might get Time Limit Exceeded Below are some of the ways to optimize the code: Minimize the use of loops inside loops i e , Nested Loops: For Example: for(i = 0 ; i < n ; i++) {for(j = 0 ; j < n ; j++) { Your Code}}
  • Speeding up independent binary searches by interleaving them
    It is hard to drastically improve on the binary search if you only need to do one But what if you need to execute multiple binary searches, over distinct lists? Maybe surprisingly, in such cases, you can multiply the speed Let us first reason about how a binary search works





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