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  • regex - How does \\d work in java? - Stack Overflow
    So, id you put it all together, this regex matches a string that has the following: Any number of any character, then a digit, and then any number of any character If we translate this "formal" description to a more human readable one, it just means a string that has a digit somewhere in it
  • regex - Using regular expressions to extract a value in Java - Stack . . .
    I want to extract the text in [some number] using the Java regex classes I know roughly what regular expression I want to use (though all suggestions are welcome) What I'm really interested in are the Java calls to take the regex string and use it on the source data to produce the value of [some number]
  • regex - Java regular expression OR operator - Stack Overflow
    This may be a dumb question, but I couldn't find it anywhere: How can I use the java OR regular expression operator (|) without parentheses? e g: Tel|Phone|Fax
  • java - How to extract a substring using regex - Stack Overflow
    Since Java 9 As of this version, you can use a new method Matcher::results with no args that is able to comfortably return Stream<MatchResult> where MatchResult represents the result of a match operation and offers to read matched groups and more (this class is known since Java 1 5)
  • Java Regex Capturing Groups - Stack Overflow
    The issue you're having is with the type of quantifier You're using a greedy quantifier in your first group (index 1 - index 0 represents the whole Pattern), which means it'll match as much as it can (and since it's any character, it'll match as many characters as there are in order to fulfill the condition for the next groups)
  • How to use regex in String. contains () method in Java
    It doesn't work with regex It will check whether the exact String specified appear in the current String or not Note that String contains does not check for word boundary; it simply checks for substring Regex solution Regex is more powerful than String contains, since you can
  • How can I provide an OR operator in regular expressions?
    Generally speaking about regexes, you definitely should begin your journey into Regex wonderland here: Regex tutorial What you currently need is the | (pipe character) To match the strings one OR other, use: (one|other) or if you don't want to store the matches, just simply one|other To be Java specific, this article is very good at
  • Java regex email - Stack Overflow
    First of all, I know that using regex for email is not recommended but I gotta test this out I have this regex: \b[A-Z0-9 _%-]+@[A-Z0-9 -]+\ [A-Z]{2,4}\b In Java, I did this: Pattern p = Pattern
  • regex - How to match any character in regular expression? - Stack . . .
    You may also sometimes need to match newlines in Java regexes in contexts where you cannot pass Pattern DOTALL, such as when doing a multi-line regex search in Eclipse, or as a user of any Java application that offers regex search
  • java - Regex match digits, comma and semicolon? - Stack Overflow
    see this page "Therefore, all the regex engines discussed in this tutorial have the option to expand the meaning of both anchors " ^ matches the beginning of a string and $ matches the end of a string So it is an option to make them match the beginning and the end of a line, but this option is not a recommendation





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